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  1. Home
  2. Oracle Certification
  3. 1z1-808 Exam
  4. Oracle.1z1-808.v2024-09-23.q208 Dumps
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Question 156

Given the code fragment:
public class Test {
static String[][] arr =new String[3][];
private static void doPrint() {
//insert code here
}
public static void main(String[] args) {
String[] class1 = {"A","B","C"};
String[] class2 = {"L","M","N","O"};
String[] class3 = {"I","J"};
arr[0] = class1;
arr[1] = class2;
arr[2] = class3;
Test.doPrint();
}
}
Which code fragment, when inserted at line //insert code here, enables the code to print
COJ?

Correct Answer: B
Incorrect:
not A: The following line causes a compile error:
System.out.println(str[j]);
Not C: Compile erro line:
for (String[] sub: arr[][])
not D: Output: C
insert code

Question 157

Given:

What is the result?

Correct Answer: A
insert code

Question 158

Given: What is the output?

Correct Answer: E
Option E is the correct answer. Code fails to compile because there is no method called concert in StringBuilder class. The concert method is in String class. Hence option E is correct Here we should have used append method of StringBuilder class, in that case option B would be correct. https://docs.oracle.com/javase/tutorial/java/data/buffers.html
insert code

Question 159

Given the code fragment: Which modification enables the code fragment to print TrueDone?

Correct Answer: A
insert code

Question 160

Given the code fragment:

What is the result?

Correct Answer: B
insert code
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