Given the JavaScript below:
01 function filterDOM (searchString) {
02 const parsedSearchString = searchString && searchString.toLowerCase() ;
03 document.quesrySelectorAll(' .account' ) . forEach(account => (
04 const accountName = account.innerHTML.toLOwerCase();
05 account. Style.display = accountName.includes(parsedSearchString) ? /*Insert code*/;
06 )};
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?

• A.' visible ' : ' hidden '
• B.' Block ' : ' none '
• C.' hidden ' : ' visible '
• D.' name ' : ' block '

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Which code statement below correctly persists an objects in local Storage ?

• A.const setLocalStorage = (storageKey, jsObject) => {
  window.localStorage.setItem(storageKey, JSON.stringify(jsObject));
  }
• B.const setLocalStorage = ( jsObject) => {
  window.localStorage.connectObject(jsObject));
  }
• C.const setLocalStorage = ( jsObject) => {
  window.localStorage.setItem(jsObject);
  }
• D.const setLocalStorage = (storageKey, jsObject) => {
  window.localStorage.persist(storageKey, jsObject);
  }

Correct Answer: A

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Refer to the code below:

What is the result of running line 05?

• A.aPromise and bPromise run sequentially.
• B.Neither aPromise or bPromise runs.
• C.Only apromise runs.
• D.Apromise and bpromise run in parallel.

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Refer to the code below:
01 const exec = (item, delay) =>{
02 new Promise(resolve => setTimeout( () => resolve(item), delay)),
03 async function runParallel() {
04 Const (result1, result2, result3) = await Promise.all{
05 [exec ('x', '100') , exec('y', 500), exec('z', '100')]
06 );
07 return `parallel is done: $(result1) $(result2)$(result3)`;
08 }
}
}
Which two statements correctly execute the runParallel () function?
Choose 2 answers

• A.runParallel () .then(data);
• B.runParallel () .then(function(data)
  return data
• C.Async runParallel () .then(data);
• D.runParallel ( ). done(function(data){
  return data;
  });

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A Developer wrote the following code to test a sum3 function that takes in an array of
numbers and returns the sum of the first three number in the array, The test passes:
Let res = sum2([1, 2, 3 ]) ;
console.assert(res === 6 );
Res = sum3([ 1, 2, 3, 4]);
console.assert(res=== 6);
A different developer made changes to the behavior of sum3 to instead sum all of the numbers
present in the array. The test passes:
Which two results occur when running the test on the updated sum3 function ?
Choose 2 answers

• A.The line 02 assertion fails
• B.The line 05 assertion fails.
• C.The line 05 assertion passes.
• D.The line 02 assertion passes.

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