You are currently working on a notebook that will populate a reporting table for downstream process consumption, this process needs to run on a schedule every hour, what type of cluster are you going to use to set up this job?

• A.Since it's just a single job and we need to run every hour, we can use an all-purpose cluster
• B.The job cluster is best suited for this purpose.
• C.Use Azure VM to read and write delta tables in Python
• D.Use delta live table pipeline to run in continuous mode

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What is the main difference between the silver layer and the gold layer in medalion architecture?

• A.Silver may contain aggregated data
• B.Gold may contain aggregated data
• C.Data quality checks are applied in gold
• D.Silver is a copy of bronze data
• E.God is a copy of silver data

Correct Answer: B

Explanation
Medallion Architecture - Databricks
Exam focus: Please review the below image and understand the role of each layer(bronze, silver, gold) in medallion architecture, you will see varying questions targeting each layer and its purpose.
Sorry I had to add the watermark some people in Udemy are copying my content.
A diagram of a house Description automatically generated with low confidence

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You have written a notebook to generate a summary data set for reporting, Notebook was scheduled using the job cluster, but you realized it takes an average of 8 minutes to start the cluster, what feature can be used to start the cluster in a timely fashion?

• A.Setup an additional job to run ahead of the actual job so the cluster is running second job starts
• B.Use the Databricks cluster pools feature to reduce the startup time
• C.Use Databricks Premium edition instead of Databricks standard edition
• D.Pin the cluster in the cluster UI page so it is always available to the jobs
• E.Disable auto termination so the cluster is always running

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Suppose there are three events then which formula must always be equal to P(E1|E2,E3)?

• A.P(E1,E2,E3)P(E1)/P(E2:E3)
• B.P(E1,E2;E3)/P(E2,E3)
• C.P(E1,E2|E3)P(E2|E3)P(E3)
• D.P(E1,E2|E3)P(E3)
• E.P(E1,E2,E3)P(E2)P(E3)

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